Cambridge International AS & A Level Chemistry Revision
Explore Cambridge International AS & A Level Chemistry revision topics. This qualification is not a GCSE; the existing guide address and saved checklist are retained. Check the official specification for complete requirements.
Qualification code: 9701
Course details
Assessment For assessment details, see the official specification.
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Reviewed course guidance
Revision points, with the explanation beside them
Open a point to read what to know, how to use it in an assessment, a plain-language explanation and a self-check. Answers stay hidden until you choose to reveal them.
Options and source
Cambridge International assessment route
- AS only: Papers 1, 2, 3
- Staged A level: AS Papers 1–3, then A level Papers 4–5
- Linear A level: Papers 1–5 in one series
Syllabus overview: AS-only, staged and linear assessment routes
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There are no fully covered explanations for these selections yet. Partial support may still appear below. Use the official specification and your teacher’s guidance.
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Topic group
Reviewed requirements
- Core
Open revision guidance
What to know
- Convert the known reactant mass to moles using its molar mass, use the balanced equation to apply the mole ratio, then convert product moles to theoretical product mass. Percentage yield = actual yield ÷ theoretical yield × 100%. Keep the stoichiometric step explicit.
What to do in an assessment
- Balance the equation before using mole ratios and check whether the stated reactant is limiting. Use actual and theoretical yields in the same units. The percentage is not validly over 100% for a correctly measured pure product.
In plain language
A balanced equation gives the amount ratio; molar masses convert between moles and grams. Yield compares what was actually obtained with the theoretical amount.
Self-check
5.00 g CaCO₃ reacts fully. CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. If 1.76 g CO₂ is collected, find the percentage yield. Use Mr(CaCO₃)=100.0 and Mr(CO₂)=44.0.
Show the answer
n(CaCO₃)=5.00/100.0=0.0500 mol, so theoretical CO₂=0.0500×44.0=2.20 g. Yield=1.76/2.20×100=80.0%.
Earlier topic checklist
These earlier topic ticks are separate from the reviewed points above and do not count towards that progress.
Chemistry topic list
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These ticks keep your earlier topic checklist. They do not count towards the new reviewed requirements above. Its numbering may be internal; use the linked references above for the exact reviewed source requirements.
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